Question 1015558
x^2+4x+10=0
x^2+4x=-10; move the constant to the right
x^2+4x+4=-10+4=-6.  Complete the square, adding the number to both sides.
(x+2)^2=-6
x+2=sqrt (-6), take the square root of both sides.
x= -2+/- i (sqrt (6))
-2+ i sqrt(6); a= -1, b=1
-2- i sqrt(6); a= -2, b=-1
{{{graph(300,200,-10,10,-10,10,x^2+4x+10)}}}