Question 1015553
Find 3 consecutive odd integers such that the second integer is 5 times the first integer, the third integer is 100 more than the first integer, and the sum of all 3 integers is 415. 
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1st:: 2x-1
2nd:: 2x+1
3rd:: 2x+3
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Note:: The conditions for your equations are contradictory.
They do not result in a consistent value for "x" and therefore
for the 3 consecutive odd integers.
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Cheers,
Stan H.
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