Question 1015553
First integer is F.
Second integer must be F+2 (consecutive odd integers) and also 5F.
So 
5F=F+2
4F=2
F=1/2
1/2 is not an integer.
.
The third integer must be F+4 (to be consecutive odd) integer and also F+100.
F+4=F+100
Obviously, this can not happen.
.
There is no solution to this problem as given.