Question 1015514
(k+3)x^2 - 2(k+1)x - (k+1) = 0
if the roots are zero, b^2-4ac=0
b^2=4ac
b^2=(-2(k+1))^2=4k^2+8k+4
4ac=4k^2+16k+12
set them equal
4k^2+8k+4=4k^2+16k+12
8k+4=16k+12
8k=-8
k=-1
2x^2=0
x=0,0