Question 1015032
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3 ml of a 66% acid solution was mixed with 8 ml of water. Find the concentration of the new mixture.
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3 ml of a 66% acid solution contains about 2 ml of the pure acid.


So, in the new mixture you have 2 ml of the pure acid per 11 ml of the total volume.


Thus the new mixture is {{{(2/11)*100}}} = 18.(18)% acid solution.