Question 1014969
I am assuming you mean
x/(x^2-1) - (x+3)/(x^2-x) = -3/(x^2+x)
or
{{{x/(x^2-1) - (x+3)/(x^2-x) = -3/(x^2+x)}}}
Next, factor the denominators
{{{x/((x-1)(x+1)) - (x+3)/(x(x-1)) = -3/(x(x+1))}}}
Working towards getting a common denominator of x(x-1)(x+1)
{{{(x/x)*(x/((x-1)(x+1))) - ((x+1)/(x+1))((x+3)/(x(x-1))) = -((x-1)/(x-1))(3/(x(x+1)))}}}
{{{x(x-1)(x+1)}}