Question 1014793
logically, if the raft holds at most 8 people and a guide and 2 people are already on the craft, then 3 people are already on the craft and at most 5 more people can board the raft.


algebraically you might solve it as follows:


let x = the number of people who are already on the raft.


let y = the additional number of people who can board the raft.


formula would be y <= 8 - x


your additional requirement would have to be be y >= 0, or x <= 8.


that would be your equation and your answer would depend on the value of x.


when x is 0, y <= 8 - 0 becomes y <= 8.
when x is 3, y <= 8 - 3 becomes y <= 5.
when x is 8, y <= 8 - 8 becomes y <= 0


but y can't be < 0, so y can only be equal to 0 in that case.