Question 87194
{{{y=2x-1}}} Start with the possible equation


{{{0=2(2)-1}}} Plug in {{{x=2}}} and  {{{y=0}}}


{{{0=3}}} Simplify. Since this is not true, the point does not lie on this line

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{{{y=(1/2)x-1}}} Start with the possible equation


{{{0=(1/2)(2)-1}}} Plug in {{{x=2}}} and  {{{y=0}}}


{{{0=0}}} Simplify. Since this is true, the point lies on this line



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{{{y=x-4}}} Start with the possible equation


{{{0=(2)-4}}} Plug in {{{x=2}}} and  {{{y=0}}}


{{{0=-2}}} Simplify. Since this is not true, the point does not lie on this line



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{{{y=3x-1}}} Start with the possible equation


{{{0=3(2)-1}}} Plug in {{{x=2}}} and  {{{y=0}}}


{{{0=5}}} Simplify. Since this is not true, the point does not lie on this line



So to recap, the point (2,0) only lies on the line {{{y=(1/2)x-1}}}