Question 1014934
the pythagorean theorem is normally stated as c^2 = a^2 + b^2


a is one leg of a right triangle.
b is the other leg of the right triangle.
c is the hyopenuse of the right triangle.


you are given that a = 8, b = ? c = 2rad97 which i assume is 2 * sqrt(97).


in the equation of c^2 = a^2 + b^2, you can solve for b to get:


b^2 = c^2 - a^2.


you know the value of a and you know the value of c, so you can replace a and c in the formula with those values to get:


b^2 = (2 * sqrt(97))^2 - 8^2


simplify this to get b^2 = 388 - 64


simplify further to get b^2 = 324


take the square root of both sides of this equation to get b = 18


your triangle now becomes:


a=8
b=18
c=2rad97


if this is true, then c^2 must be equal to a^2 + b^2 because pythagorus proved that it had to be way back in the days of ancient greece.


so (2 * sqrt(97))^2 must be equal to 8^2 + 18^2 if we calculated b correctly.


8^2 + 18^2 = 64 + 324 = 388


(2 * sqrt(97))^2 is also equal to 388.


the equation is confirmed to be true and your solution is that the value of b is 18.


here's a reference regarding the pythagorean theorem.


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