Question 1014924
Solve the system of equations {{{y = x^2 -x +k - 1}}} and y = x + 1.

Then {{{x^2 -x +k - 1 = x +1}}} , or {{{x^2 -2x +k - 2=0}}} .

The discriminant is then equal to {{{b^2 - 4ac = 4 - 4(1)(k-2) = 12 - 4k}}}.

Since it is given that k > 4, it follows that:

-4k < -16,
12 - 4k < 12 - 16 = -4,
12 - 4k < -4 < 0,
hence the discriminant is negative, and thus the system has no (real) solutions.  Therefore the two graphs don't have points in common.  (They do not intersect.)