Question 1014925
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Edit:
Sorry for the post that {{{highlight(cross(have))}}} has insufficient data, i checked again the problem and here it is:

y varies directly as the cube of x and square of z. If y = 5 {{{highlight(cross(if))}}} when x = 2, & z = 3, what is y if x = 4 & z = 9?

thank you
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O, this one is much better!


<U>Answer</U>. Then y = {{{5}}} * {{{2^3}}} * {{{3^2}}} = 5*8*9 = 360.
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