Question 1014639
For n number of heads,
{{{P(n)=C(6,n)*(1/2)^n*(1/2)^(6-n)}}}
{{{P(n)=C(6,n)*(1/2)^(6)}}}
{{{P(n)=C(6,n)/64}}}
a) At leas6t 5 heads is the sum of 5 and 6 heads,
{{{P=P(5)+P(6)=C(6,5)/64+C(6,6)/64=(6+1)/64=7/64}}}
b) At least 3 heads is the sum of 3,4,5 and 6 heads,
{{{P=P(3)+P(4)+7/64=C(6,3)+C(6,4)+7/64=(20+15)/64+7/64=42/64=21/32}}}
c) {{{P(0)=1/64}}}
d) At most 2 tails is (0,1,2) tails or (6,5,4) heads,
{{{P=P(4)+P(5)+P(6)=(15+7)/64=22/64=11/32}}}