Question 1741
s^2 = the area of the first square
(s+1)^2 = the area of the second square
(s+2)^2 = the area of the third square
s^2 + (s+1)^2 + (s+2)^2 = the area of the sum of the three squares
s^2 + s^2 + 2s + 1 + s^2 + 4s + 4 = 365
3s^2 + 6s -360 = 0
Use the quardratic formula
{{{x=(6+-sqrt(6^2-4(3)(-360)))/(2(3))}}}
{{{x=(6+-sqrt(4356))/6}}}
{{{x=(6+-66)/6}}}
x = 72/6 or -60/6
x = 12 or -10
Since length can not be a negative number, 12 is the answer
s = 12
s+1 = 13
s+2 = 14