Question 1014689
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The graphs of the two functions you presented are not even close to being identical, nor is there a "hole" in either one.  You have a typo.  Correct it and repost.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  

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