Question 1014678
The Perimeter of a certain playing field is 222ft the field is a rectangle, and the length is 49 ft longer then the width. Find the dimensions
2l+2w = 222 Your problem says that l= w+49, so substitute:
2(w+49)+2w = 222
2w+98+2w= 222 Add w on left and subtract 98 on both sides:
4w= 124 Divide both sides by 4:
w= 31 and the length:
31+49= 80