Question 1014659
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How to solve the equation  x^2-15x +50=0 . Write the answers in ascending order.
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Factor left side polynomial:

{{{x^2-15x +50}}} = (x-5*)(x-10).

Then your equation becomes 

(x-5*)(x-10) = 0.

It has the roots 5 and 10.

They are the roots of the original equation too.
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