Question 1014628
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Yes
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x^2-3=0
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roots (zeroes) at +/-{{{sqrt(3)}}}
The roots are real, but not rational.
(The square root of three is not rational)
Real (not complex) roots are always x-intercepts 
on the graph of the function. Imaginary roots are not. 
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On the graph below:
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{{{f(x)=x^2-3}}} Red line below, has irrational real roots
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{{{f(x)=x^2+3}}} Green line below, has imaginary (not real) roots,
and does not intercept x axis.
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{{{ graph( 800, 800, -10, 10, -10, 10, x^2-3, x^2+3) }}}
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The rational roots test gives possible rational roots.
If there are rational roots,they are given by this test.
The test does not determine if any of the possibilities
are actually roots.