Question 1014614
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Use the following theorems:


Theorem 1: A quadrilateral is a parallelogram if and only if the diagonals bisect each other.


Theorem 2: Vertical angles are congruent


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EFGH is a parallelogram -- Given


K bisects EG by Theorem 1.


EK is congruent to KG by definition of bisector


K bisects FH by Theorem 1


FK is congruent to KH by definition of bisector


Angle EKF is congruent to angle HKG by Theorem 2


Triangle EFK is congruent to triangle GHK by SAS.


QED


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  

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