Question 1014604
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T=amount of 20% alloy; S=amount of 60% alloy
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T+S=80
T=80-S
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0.20T+0.60S=0.44(80)
0.20(80-S)+0.60S=35.2
16.0-0.20S+0.60S=35.2
0.40S=19.2
S=48
ANSWER 1: He should use 48 kg of 60% alloy.
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T=80-S=80-48=32
ANSWER 2: He should use 32 kg of 20% alloy.
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CHECK:
0.20T+0.60S=0.44(80)
0.20(32)+0.60(48)=35.2
6.4+28.8=35.2
35.2=35.2
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