Question 1014499
.
A jeepney accelerates uniformly over a time of 3.25 seconds and covers a distance of 15 meters.Determine the acceleration of the jeepney?
------------------------------------------------------


<pre>
Your equation is 

S = {{{(at^2)/2}}}

where S is the distance (meters), a is an uniform acceleration {{{m/s^2}}} and t is time (sec).

When you substitute your data, you will get

15 = {{{(a*3.25^2)/2}}},   or

30 = a*10.5625.

Then a = {{{30/10.5625}}} = 1.42 {{{m/s^2}}}.
</pre>