Question 1014478
Find Three consecutive odd integers such their sum decreased by the second equals 50 
<pre>Let the first integer be F
Then other 2 are: F + 2, and F + 4
We then get: F + F + 2 + F + 4 - (F + 2) = 50
Solve for F, the 1<sup>st</sup> integer, then F + 2, and F + 4, for the 2<sup>nd</sup> and 3<sup>rd</sup>, respectively
Hint: You should get F, or 1st integer as 23.