Question 1014331
let a be the area of rectangle A.
let b be the area of rectangle B.


a + b = 39
2a + b/3 = 33


multiply the second equation by 3 and keep the first equation the same to get:


a + b = 39
6a + b = 99


subtract the second equation from the first to get:


-5a = -60


divide both sides of this equation by -5 to get:


a = 12


since a + b = 33, then b must be equal to 27


area of rectangle A is equal to 12.
area of rectangle B is equal to 27.


a + b = 12 + 27 = 39
this checks out ok.


2a + b/3 = 2*12 + 27/3 = 24 + 9 = 33
this checks out ok as well.


your solution is:


area of rectangle A is equal to 12 square units.
area of rectangle B is equal to 27 square units.