<PRE><B>Question 1014404</B>
 Bob flies an airplane 495 miles with a tail wind of 25 miles per hour. Against the wind, he flies only 405 miles in the same amount of time. Find the rate of the plane in still air. 
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With-wind DATA:
dist = 495 miles ; rate = p+25 mph ; time = d/r = 495/(p+25) hrs
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Against-wind DATA:
dist = 405 miles ; rate = p-25 mph ; time = 405/(p-25) hrs
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Equation:
time = time
495/(p+25) = 405/(p-25)
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495p - 495*25 = 405p + 25*405
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90p = 22500
plane speed = 250 mph
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Cheers,
Stan H.
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