Question 87115
I'm not sure how you generated the table but you should reread the problem and check your calculations


if x is the length (and width) of the cut-out squares, then the length (and width) of the resulting folded box is 12-2x ... the height of the folded box is x


the volume of a box is length times width times height ... v=(12-2x)(12-2x)x ... v=144x-48x^2+4x^3


the cardboard is 12x12 so the largest the cut-out squares can be is 6 ... so the domain is 0<=x<=6