Question 1014158
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x and x+2 are consecutive odd integers
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{{{(x)(x+2)=8(x+x+2)+79}}}
{{{x^2+2x=8(2x+2)+79}}}
{{{x^2+2x=16x+16+79}}}
{{{x^2+2x=16x+95}}}
{{{x^2-14x-95=0}}}
{{{(x-19)(x+5)=0}}}
{{{x-19=0}}} {{{OR}}} {{{x+5=0}}}
{{{x=19}}} {{{OR}}} {{{x=-5}}}
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ANSWER: The integers are 19 and 21 or -5 and -3.
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CHECK:
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For 19 and 21:
{{{(19)(21)=8(19+21)+79
{{{399=8(40)+79}}}
{{{399=320+79}}}
{{{399=399}}}
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For -5 and -3:
{{{(-5)(-3)=8(-5+(-3))+79}}}
{{{15=8(-8)+79}}}
{{{15=-64+79}}}
{{{15=15}}}
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