Question 1014033
<pre>
Method 1: By writing the exponents as repeated multiplications,
breaking 4 into prime factors and cancelling:


{{{(-3*a^3*b^2)(4*a*b)/ (2*a^7*b)}}}

{{{(-3*a*a*a*b*b)(2*2*a*b)/ (2*a*a*a*a*a*a*a*b)}}}


{{{(-3*cross(a)*cross(a)*cross(a)*cross(b)*b)(cross(2)*2*cross(a)*b)/ (cross(2)*cross(a)*cross(a)*cross(a)*cross(a)*a*a*a*cross(b))}}}

{{{(-3*b)(2*b)/ (a*a*a)}}}

{{{-(6b^2)/a^3}}}

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Method 2: By adding exponents to multiply and then subtracting
exponents to divide:

{{{(-3*a^3*b^2)(4*a*b)/ (2*a^7*b)}}}

{{{(-12*a^4*b^3)/ (2*a^7*b)}}}

Divide the -12 on the top by the 2 on the bottom, getting -6 on the
top.

Subtract the exponents of "a", 7-4 getting exponent 3 and putting 
a<sup>3</sup> on the bottom because the larger exponent of "a" was 
on the bottom.

Subtract the exponents of "b", 3-1 (understood) getting exponent 2 
and putting b<sup>2</sup> on the top because the larger exponent of 
"b" was on the top. 

{{{-(6b^2)/a^3}}}

Edwin</pre>