Question 87065
Let x=the first number
And y=the second number
Now we are told that one number is two more than a second number. So we have:

x=y+2-------------------------eq1

We are also told that twice the first number is four less than 3 times the second number.  And this gives us:

2x=3y-4----------------------------eq2

From eq1, substitute x=y+2 into eq2:

2(y+2)=3y-4  get rid of parens

2y+4=3y-4  subtract 3y and also 4 from both sides

2y+4-4-3y=3y-3y-4-4  collect like terms

-y=-8  divide both sides by -1

y=8  ----------------------------the second number

From eq1, x=y+2 or x=8+2=10------------------------the first number

CK
one number(10) is 2 more than the second number(8)----------------ok

twice the first number(20) is four less than 3 times the second number(24-4=20)---ok


Hope this helps---ptaylor