Question 1013986

Shorter leg of a right triangle is 7ft shorter than the longer leg.
The hypotenuse is 7ft longer than the longer leg. 
Find the side lengths of the triangle.

I cant seem to get my head around this.

(x-7^2)+(x+7^2)=??  Sorry, pretty fresh to this.
<pre>Let the length of the longer leg, be L
Then the length of the shorter leg is: L - 7, and length of hypotenuse is: L + 7 
Using Pythagorean theorem: {{{a^2 + b^2 = c^2}}}, we get: {{{L^2 + (L - 7)^2 = (L + 7)^2}}}
Can you now solve this for L, the longer leg, and subsequently, the shorter leg and the hypotenuse?
If not, say so, and you might get further help!