Question 1013833
x^3 -5x^2 -9x+45=0
rational zeros are +/- 1,3,5,9,15,and 45, the factors of the constant divided by the factors of x^3.
using synthetic division with 3. By looking at the division, 1 did not look like it would work, so I went to 3.  If that didn't work, I would try -3. Then I would try 5 or -5.
1;;;;-5;;;;-9;;;;-45
1;;;;-2;;;;-15---0
Therefore,(x-3) is a factor, and what is left over is  x^2-2x+15.  That factors to (x-5)(x+3).  
roots are -3,3, and 5.
{{{graph(300,200,-10,10,-10,10,x^3-5x^2-9x+45)}}}