Question 1013809
Call the larger and the smaller, x and y.  Then we have
x + y = 11  (or x = 11 - y) 
and

3x - 2y = 8
Now substitute and get
3(11-y) - 2y = 8
33 - 3y - 2y = 8
-5y + 33 = 8
-5y = -25
y = 5
x = 6