Question 1013686
A regular hexagon is actually composed of six equilateral triangles.  The area of an equilateral triangle is
{{{A = s^2*sqrt(3)/4}}}
Thus the area of the hexagon is 6 times that, so we have
{{{A[hex] = 6*s^2*sqrt(3)/4 = 6*6^2*sqrt(3)/4 = 54*sqrt(3)}}} =
93.5 sq. in.