Question 1013511
{{{2x^3+3x^2 +2x +3=0}}}........easiest way is to factor it completely and use zero product theorem

{{{(2x^3+3x^2) +(2x +3)=0}}}

{{{x^2(2x+3) +(2x +3)=0}}}

{{{(x^2+1)(2x +3)=0}}}


if {{{(x^2+1)=0}}}=>{{{x^2=-1}}}=>{{{x=sqrt(-1)}}}=>{{{highlight(x=i)}}} or =>{{{highlight(x=-i)}}}-> two complex solutions

if {{{(2x +3)=0}}}=>{{{2x=-3}}}=>{{{highlight(x=-3/2)}}}-> one real solution