Question 1013465
Since {{{(3/5)(4/5)}}} is not a perfect square,
{{{sqrt((3/5)(4/5))}}} is an irrational number between 3/5 and 4/5.
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{{{sqrt((3/5)(4/5)))=sqrt(12/25)}}}={{{sqrt(12)/5=2sqrt(3)/5}}}
ANSWER 1: First irrational number between 3/5 and 4/5 is {{{2sqrt(3)/5}}}
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Since {{{(3/5)(2sqrt(3)/5)}}} is not a perfect square, 
{{{sqrt((3/5)(2sqrt(3)/5))}}} is an irrational number between 3/5 and {{{2sqrt(3)/5}}}.
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{{{sqrt((3/5)(2sqrt(3)/5))=sqrt(6sqrt(3)/25)}}}={{{sqrt(6sqrt(3))/5}}}
ANSWER 2: A second irrational number between 3/5 and 4/5 is {{{sqrt(6sqrt(3))/5}}}
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Since {{{(4/5)(2sqrt(3)/5)}}} is not a perfect square, 
{{{sqrt((4/5)(2sqrt(3)/5))}}} is an irrational number between 4/5 and {{{2sqrt(3)/5}}}.
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{{{sqrt((4/5)(2sqrt(3)/5))=sqrt(8sqrt(3)/25)}}}={{{sqrt(8sqrt(3))/5}}}
ANSWER 2: A third irrational number between 3/5 and 4/5 is {{{sqrt(8sqrt(3))/5}}}={{{ 2(sqrt(2sqrt(3)))/5}}}
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