Question 1013468
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{{{csc^2(theta)=cot^2(theta)+1}}}
{{{0=cot^2(theta)+1-csc^2(theta)}}}
{{{-cot^2(theta)=1-csc^2(theta)}}}
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{{{(1-csc^2(theta))/(cot(theta))}}}={{{(-cot^2(theta))/cot(theta)=((-1)(cot(theta))(cot(theta)))/(cot(theta))}}}={{{-cot(theta)}}}