Question 1013371
10x + 15y >= 300


to graph, solve for y in terms of x.


start with 10x + 15y >= 300.
subtract 10x from both sides of the equation to get 15y >= 300 - 10x.
divide both sides of the equation by 15 to get y >= (300 - 10x)/15.


graph that equation.


all values of y on the line or above the line are what you are looking for.


look below the graph for further comments.


<img src = "http://theo.x10hosting.com/2016/011201.jpg" alt="$$$" </>


on or above the line is the white area in the graph.


this area satisfies the requirements of the equation.


this area also satisfies the requirement that x be greater than or equal to 0 and y be greater than or equal to 0.


when x = 0, y has to be equal to or above 20.


when x = 30, y has to be equal to or above 0.


when x = 60, y has to be equal to or above 0.


the vertical and horizontal dashed lines are sample values that are valid.


the bottom line is that any area on the graph that is white is valid because it satisfies the requirement that 10x + 15y >= 300 and it also satisfies the requirement that x >= 0 and y >= 0.


without all those vertical and horizontal dashed lines, the graph would look like this:


the area on the graph that satisfies the eqution is the area that  is above and to the right of the line of the equation as well as the area that is above the x-axis and to the right of the y-axis.


{{{graph(600,600,-5,40,-5,40,(300-10x)/15)}}}