Question 1013364
Look at the cube root of 21924 almost 28
26*27*28 does not have a 4 for the final digit, but 27*28*29 does.
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Alternatively,
numbers are x, x+1, x+2
(x^2+x)(x+2)=x^3+3x^2x=21924
x^3+3x^2+2x-21924=0
x=27
{{{graph(300,200,-10,30,-20000,20,x^3+3x^2+2x-21924)}}}