<PRE><B>Question 1013113</B>
A normal distribution has a mean of 20 and a standard deviation of 4. What is the z-score of a value that is 0.52 standard deviations less than the mean 
----------
x = z*s + u
-------
x = 0.52*4 + 20
-----
x = 2.08 + 20
------
x = 22.08
---------------
Cheers,
Stan H.
-------------</PRE>