Question 1013260
In Triangle CAB, BC is extended through point D. Angle CAB = 38 degrees, 
side AC (or angle ACD)= 2x-5, and BC = x+3.
:
What is the measure of angle ACD?

Is this drawn as a right triangle, angle B = 90 degrees?
then
angle ACB = 180 - 90 - 38 = 52 degrees
therefore
angle ACD = 180 - 52 = 128 degrees
Also
sin(38) = {{{((x+3))/((2x-5))}}}
.61566 = {{{((x+3))/((2x-5))}}}
.62566(2x-5) = x + 3
1.23x - 3.078 = x + 3
1.23x - x = 3 + 3.078
.23x = 6.078
x = {{{6.078/.23}}}
x = 26.427
:
What is the measure of BC?
26.427 + 3 = 23.427
:
:
If this is not a right triangle none of this applies, it becomes a much more complicated problem