Question 86994
the vertex angle of an isosceles triangle is 57degrees 24 minutes and each of its equal sides is 375.5 ft. long. find the altitude of the triangle.
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Draw the picture.the vertex angle of an isosceles triangle is 57degrees 24 minutes and each of its equal sides is 375.5 ft. long. find the altitude of the triangle.
Each of the base angles is (1/2)(180 - 57 degrees 24') = (1/2)(122 degrees 36')
= 62 degrees 18'
Comment: 62 degrees 18' = 62.3 degrees
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Draw the altitude.
EQUATION:
sin(62.3) = altitude/375.5
altitude = 375.5*sin(62.3)
altitude = 332.47 ft.
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Cheers,
Stan H.