Question 1013202

The measure of the smallest angle of a triangle is one-third measure of the largest angle. The measure of the second angle is 51* less than the measure of the largest angle. Fine the measure of the angles of the triangles. 
<pre>Let smallest angle be S
Then largest angle = 3S, and 2<sup>nd</sup>/middle angle = 3S - 51
We then get: S + 3S + 3S - 51 = 180
Solve for S, the smallest angle, then the largest and the 2<sup>nd</sup>, not necessarily in that order.