Question 1013154

{{{x+2y=10}}}.........eq.1
{{{2x-y=5}}}..........eq.2
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using the substitution method, first solve {{{x+2y=10}}}.........eq.1 for {{{x}}}

{{{x=10-2y}}}.........substitute it in eq.2

{{{2(10-2y)-y=5}}}........solve for {{{y}}}

{{{20-4y-y=5}}}

{{{20-5y=5}}}

{{{20-5=5y}}}

{{{15=5y}}}

{{{15/5=y}}}

{{{highlight(y=3)}}}

now substitute it in {{{x=10-2y}}} and find {{{x}}}

{{{x=10-2*3}}}

{{{x=10-6}}}

{{{highlight(x=4)}}}