Question 1013138
See the other example you asked for a few minutes ago.  The method  (substitution used) can work the same way.  (I had solved for one of the variables, but for the other variable, I merely did not finish the computation).


{{{0.60}}}-----Another way to manage this is, understand meaning of decimals.
{{{0.60=60/100=6/10=(2*3)/(2*5)}}}
{{{(2/2)(3/5)}}}
{{{1*(3/5)}}}
{{{3/5}}}.


That money equation is therefore equivalent to  {{{(3/5)x+2y+200}}}.