Question 1013124
Slightly different example than posted earlier but at least it is complete enough to solve.


x, cups
y, cones


{{{system(x+y=164,0.6x+0.75y=200)}}}



First simplify the money equation.
{{{12x+15y=4000}}}


System can be {{{system(x+y=164,12x+15y=4000)}}}, and Elimination Method may be best method to choose...


{{{system(12x+12y=1968,12x+15y=4000)}}}


E2-E1 --------  {{{3y=2032}}}
But this does not work too well because {{{highlight_green(y=677&1/3)}}}.


Maybe a reason for that, or maybe not.   (Include one third of a cone?  Possibly if a cone gets more than one scoop of ice-cream.)



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Elimination Method really is a form of Substitution, often being more efficient.


If you multiply left and right members of 0.6x+0.75y=200  by 20, you will get the equivalent equation,  12x+15y=4000.