Question 1013108
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Solve x^4 +4x^2 = 32. Find 4 roots. 
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{{{x^4 +4x^2}}} = 32,  

{{{(x^2+2)^2}}} - 4 = 32,

{{{(x^2+2)^2}}} = 36,

{{{(x^2+2)}}} = +/- 6.

Now solve two quadratic equations 

1. {{{x^2+2}}} = 6  ---->  {{{x^2}}} = 4  ---->  Two solutions: x = 2 and x = -2.

2. {{{x^2+2}}} = -6  ---->  {{{x^2}}} = -8  ---->  Two solutions: x = {{{2i*sqrt(2)}}} and x = {{{-2i*sqrt(2)}}}.

You obtain four solutions, in total.
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