Question 1013100
N=number of cones; C=number of cups
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Solve for N:
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$2N+$0.60C=$200
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$2N=$200-$0.60C
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N=($200-$0.60C)/$2
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N=($200/$2)-($0.60/$2)C
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N=100-0.3C
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Solve for C:
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$2N+$0.60C=$200
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$0.60C=$200-$2N
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C=($200-$2N)/$0.60
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C=($200/$0.60)-($2/$0.60)N
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C=333.33-3.33N
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C=3.33(100-N)
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With the information given, this is as far as we can go.
If we knew total number of units sold, we could find a
numerical answer.
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