Question 1013065
.
The sum of the squares of the first "n" counting numbers
is given by:
. 
Sum={{{(n(n+2)(2n+1))/6}}}
.
The median is the sum/n.
.
median = {{{((n(n+2)(2n+1))/6)/n}}}={{{(n(n+2)(2n+1))/(6n)}}}