Question 1013022

{{{2x-3y=12}}}

set {{{y=0}}} to find the x-intercept

{{{2x-3*0=12}}}

{{{2x=12}}} 

{{{x=12/2}}} 

{{{x=6}}} 

so,  the x-intercept is at ({{{6}}},{{{0}}} )

 
and 

set {{{x=0}}} to find the y- intercept 

{{{2*0-3y=12}}}

{{{-3y=12}}}

{{{y=12/-3}}}

{{{y=-4}}}

 the y-intercept is at ({{{0}}},{{{-4}}} )



{{{ graph( 600, 600, -10, 10, -10, 10,(2/3)x-4) }}}