Question 1013015
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Solve algebraically for all values of x:

x^4 +4x^3 +4x^2 = -16x
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{{{x^4 +4x^3 +4x^2 + 16x}}} = {{{0}}}.

Factor taking x out of parentheses

{{{x*(x^3 + 4x^2 + 4x + 16)}}} = {{{0}}}.

Factor further the third degree polynomial by grouping

{{{x*((x^3 + 4x^2) + (4x + 16))}}} = {{{0}}},

{{{x*(x^2(x+4) + 4*(x+4))}}} = {{{0}}},

{{{x*(x^2 + 4)*(x+4)}}} = {{{0}}}.

Everything is clear now, isn't it?
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