Question 1012978
The general term will be  {{{cross(b[n]=3^(n-1))}}}.
General term is  {{{3*2^(n-1)}}}


{{{b[2015]=3*2^(2014)=cross(8.3600140129806392468037591442514e+960)}}}
... is 5.6432919934120158375092217504285e+606


or about {{{5.64329*10^606}}}




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Corrected mistake