Question 1012933


Since the number n is divisible by {{{3}}}, the number {{{n^2}}} is divisible by {{{9}}}. 
By the divisibility rules, a number is divisible by {{{9}}} if the {{{sum}}} of its digits is divisible by {{{9}}}. 
Therefore, {{{3 + 6 + 4 + 1 + A + 5 = A + 19}}}  must be divisible by {{{9}}}. 
Now, since {{{A }}}is a 1-digit number, the only possible value for {{{A = 8}}}  since {{{19 + 8 = 27 }}} and {{{27}}} is divisible by {{{9}}}. Therefore, {{{ A = 8}}}.